Proof: Square

Let's prove the following theorem:

((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)) = (a ⋅ a) + (b ⋅ b)

Proof:

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Proof Table
# Claim Reason
1 ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b)
2 ((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2)) = 0 ((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2)) = 0
3 ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = (((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + ((a ⋅ a) + (b ⋅ b)) ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = (((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + ((a ⋅ a) + (b ⋅ b))
4 ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = 0 + ((a ⋅ a) + (b ⋅ b)) if ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = (((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + ((a ⋅ a) + (b ⋅ b)) and ((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2)) = 0, then ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = 0 + ((a ⋅ a) + (b ⋅ b))
5 0 + ((a ⋅ a) + (b ⋅ b)) = (a ⋅ a) + (b ⋅ b) 0 + ((a ⋅ a) + (b ⋅ b)) = (a ⋅ a) + (b ⋅ b)
6 ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = (a ⋅ a) + (b ⋅ b) if ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = 0 + ((a ⋅ a) + (b ⋅ b)) and 0 + ((a ⋅ a) + (b ⋅ b)) = (a ⋅ a) + (b ⋅ b), then ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = (a ⋅ a) + (b ⋅ b)
7 ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)) ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b))
8 ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)) = ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) if ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)), then ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)) = ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)
9 ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = (a ⋅ a) + (b ⋅ b) if ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) and ((((a ⋅ b) ⋅ 2) + ((a ⋅ b) ⋅ (-2))) + (a ⋅ a)) + (b ⋅ b) = (a ⋅ a) + (b ⋅ b), then ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = (a ⋅ a) + (b ⋅ b)
10 ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)) = (a ⋅ a) + (b ⋅ b) if ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)) = ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) and ((((a ⋅ b) ⋅ 2) + (a ⋅ a)) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b) = (a ⋅ a) + (b ⋅ b), then ((a ⋅ b) ⋅ 2) + (((a ⋅ a) + ((a ⋅ b) ⋅ (-2))) + (b ⋅ b)) = (a ⋅ a) + (b ⋅ b)
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