Proof: Subtract Both Sides
Let's prove the following theorem:
if a = b + c, then a + (c ⋅ (-1)) = b
Proof:
Given
| 1 | a = b + c |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | a + (c ⋅ (-1)) = b + (c + (c ⋅ (-1))) | if a = b + c, then a + (c ⋅ (-1)) = b + (c + (c ⋅ (-1))) |
| 2 | b + (c + (c ⋅ (-1))) = b | b + (c + (c ⋅ (-1))) = b |
| 3 | a + (c ⋅ (-1)) = b | if b + (c + (c ⋅ (-1))) = b and a + (c ⋅ (-1)) = b + (c + (c ⋅ (-1))), then a + (c ⋅ (-1)) = b |
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