Proof: Byte 7 Stays the Same 11
Let's prove the following theorem:
if the following are true:
- instruction #4 is
addi dst=4 src=4 imm=1
- the PC at time 11 = 4
- value of cell 7 at time 11 = 31
then value of cell 7 at time 12 = 31
Proof:
Given
1 | instruction #4 is addi dst=4 src=4 imm=1 |
---|---|
2 | the PC at time 11 = 4 |
3 | value of cell 7 at time 11 = 31 |
# | Claim | Reason |
---|---|---|
1 | not (7 = 4) | not (7 = 4) |
2 | value of cell 7 at time (11 + 1) = value of cell 7 at time 11 | if instruction #4 is addi dst=4 src=4 imm=1 and the PC at time 11 = 4 and not (7 = 4), then value of cell 7 at time (11 + 1) = value of cell 7 at time 11 |
3 | 11 + 1 = 12 | 11 + 1 = 12 |
4 | value of cell 7 at time (11 + 1) = value of cell 7 at time 12 | if 11 + 1 = 12, then value of cell 7 at time (11 + 1) = value of cell 7 at time 12 |
5 | value of cell 7 at time 12 = value of cell 7 at time 11 | if value of cell 7 at time (11 + 1) = value of cell 7 at time 12 and value of cell 7 at time (11 + 1) = value of cell 7 at time 11, then value of cell 7 at time 12 = value of cell 7 at time 11 |
6 | value of cell 7 at time 12 = 31 | if value of cell 7 at time 12 = value of cell 7 at time 11 and value of cell 7 at time 11 = 31, then value of cell 7 at time 12 = 31 |
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