Proof: Subtract Move Over
Let's prove the following theorem:
if a - b = c, then a = c + b
Proof:
Given
| 1 | a - b = c |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | (a - b) + b = c + b | if a - b = c, then (a - b) + b = c + b |
| 2 | a - b = a + (b ⋅ (-1)) | a - b = a + (b ⋅ (-1)) |
| 3 | (a - b) + b = (a + (b ⋅ (-1))) + b | if a - b = a + (b ⋅ (-1)), then (a - b) + b = (a + (b ⋅ (-1))) + b |
| 4 | (a + (b ⋅ (-1))) + b = a + ((b ⋅ (-1)) + b) | (a + (b ⋅ (-1))) + b = a + ((b ⋅ (-1)) + b) |
| 5 | (b ⋅ (-1)) + b = 0 | (b ⋅ (-1)) + b = 0 |
| 6 | (a + (b ⋅ (-1))) + b = a + 0 | if (a + (b ⋅ (-1))) + b = a + ((b ⋅ (-1)) + b) and (b ⋅ (-1)) + b = 0, then (a + (b ⋅ (-1))) + b = a + 0 |
| 7 | a + 0 = a | a + 0 = a |
| 8 | (a + (b ⋅ (-1))) + b = a | if (a + (b ⋅ (-1))) + b = a + 0 and a + 0 = a, then (a + (b ⋅ (-1))) + b = a |
| 9 | (a - b) + b = a | if (a - b) + b = (a + (b ⋅ (-1))) + b and (a + (b ⋅ (-1))) + b = a, then (a - b) + b = a |
| 10 | a = c + b | if (a - b) + b = a and (a - b) + b = c + b, then a = c + b |
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