Proof: Multiply Reorder 2
Let's prove the following theorem:
(a ⋅ b) ⋅ c = (b ⋅ c) ⋅ a
Proof:
| # | Claim | Reason |
|---|---|---|
| 1 | a ⋅ b = b ⋅ a | a ⋅ b = b ⋅ a |
| 2 | (a ⋅ b) ⋅ c = (b ⋅ a) ⋅ c | if a ⋅ b = b ⋅ a, then (a ⋅ b) ⋅ c = (b ⋅ a) ⋅ c |
| 3 | (b ⋅ a) ⋅ c = (b ⋅ c) ⋅ a | (b ⋅ a) ⋅ c = (b ⋅ c) ⋅ a |
| 4 | (a ⋅ b) ⋅ c = (b ⋅ c) ⋅ a | if (b ⋅ a) ⋅ c = (b ⋅ c) ⋅ a and (a ⋅ b) ⋅ c = (b ⋅ a) ⋅ c, then (a ⋅ b) ⋅ c = (b ⋅ c) ⋅ a |
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