Algebra 1 / Chapter 2: Multiplication / Properties of Multiplication
Proof: Square Product Theorem
Let's prove the following theorem:
if a = b ⋅ c, then a ⋅ a = ((b ⋅ c) ⋅ b) ⋅ c
Proof:
Given
| 1 | a = b ⋅ c |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | a ⋅ a = (b ⋅ c) ⋅ (b ⋅ c) | if a = b ⋅ c, then a ⋅ a = (b ⋅ c) ⋅ (b ⋅ c) |
| 2 | (b ⋅ c) ⋅ (b ⋅ c) = ((b ⋅ c) ⋅ b) ⋅ c | (b ⋅ c) ⋅ (b ⋅ c) = ((b ⋅ c) ⋅ b) ⋅ c |
| 3 | a ⋅ a = ((b ⋅ c) ⋅ b) ⋅ c | if (b ⋅ c) ⋅ (b ⋅ c) = ((b ⋅ c) ⋅ b) ⋅ c and a ⋅ a = (b ⋅ c) ⋅ (b ⋅ c), then a ⋅ a = ((b ⋅ c) ⋅ b) ⋅ c |
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