Proof: Vertical Angles ASA
Let's prove the following theorem:
if M is the midpoint of line AB and m∠XMY = 180 and ∠MAY is a right angle and ∠MBX is a right angle, then △YMA ≅ △XMB
Proof:
Given
| 1 | M is the midpoint of line AB |
|---|---|
| 2 | m∠XMY = 180 |
| 3 | ∠MAY is a right angle |
| 4 | ∠MBX is a right angle |
| # | Claim | Reason |
|---|---|---|
| 1 | distance AM = distance MB | if M is the midpoint of line AB, then distance AM = distance MB |
| 2 | distance MA = distance AM | distance MA = distance AM |
| 3 | distance MA = distance MB | if distance MA = distance AM and distance AM = distance MB, then distance MA = distance MB |
| 4 | m∠AMB = 180 | if M is the midpoint of line AB, then m∠AMB = 180 |
| 5 | m∠YMA = m∠XMB | if m∠XMY = 180 and m∠AMB = 180, then m∠YMA = m∠XMB |
| 6 | m∠MAY = 90 | if ∠MAY is a right angle, then m∠MAY = 90 |
| 7 | m∠MBX = 90 | if ∠MBX is a right angle, then m∠MBX = 90 |
| 8 | m∠MAY = m∠MBX | if m∠MAY = 90 and m∠MBX = 90, then m∠MAY = m∠MBX |
| 9 | △YMA ≅ △XMB | if m∠YMA = m∠XMB and distance MA = distance MB and m∠MAY = m∠MBX, then △YMA ≅ △XMB |
Comments
Please log in to add comments