Proof: Rectangle Diagonals Congruent
Let's prove the following theorem:
if WXYZ is a rectangle, then distance WY = distance XZ
Proof:
Given
| 1 | WXYZ is a rectangle |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | WXYZ is a parallelogram | if WXYZ is a rectangle, then WXYZ is a parallelogram |
| 2 | distance WZ = distance XY | if WXYZ is a parallelogram, then distance WZ = distance XY |
| 3 | distance XY = distance WZ | if distance WZ = distance XY, then distance XY = distance WZ |
| 4 | ∠ZWX is a right angle | if WXYZ is a rectangle, then ∠ZWX is a right angle |
| 5 | ∠WXY is a right angle | if WXYZ is a rectangle, then ∠WXY is a right angle |
| 6 | m∠ZWX = 90 | if ∠ZWX is a right angle, then m∠ZWX = 90 |
| 7 | m∠WXY = 90 | if ∠WXY is a right angle, then m∠WXY = 90 |
| 8 | m∠ZWX = m∠WXY | if m∠ZWX = 90 and m∠WXY = 90, then m∠ZWX = m∠WXY |
| 9 | m∠WXY = m∠XWZ | if m∠ZWX = m∠WXY, then m∠WXY = m∠XWZ |
| 10 | distance WX = distance XW | distance WX = distance XW |
| 11 | △WXY ≅ △XWZ | if distance WX = distance XW and m∠WXY = m∠XWZ and distance XY = distance WZ, then △WXY ≅ △XWZ |
| 12 | distance WY = distance XZ | if △WXY ≅ △XWZ, then distance WY = distance XZ |
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