Proof: If Diagonals Perpendicular Then Rhombus
Let's prove the following theorem:
if WXYZ is a parallelogram and ∠YPZ is a right angle and m∠WPY = 180 and m∠XPZ = 180, then WXYZ is a rhombus
Proof:
Proof Table
| # | Claim | Reason |
|---|---|---|
| 1 | △PYZ ≅ △PWX | if WXYZ is a parallelogram and m∠WPY = 180 and m∠XPZ = 180, then △PYZ ≅ △PWX |
| 2 | distance YP = distance WP | if △PYZ ≅ △PWX, then distance YP = distance WP |
| 3 | distance WP = distance YP | if distance YP = distance WP, then distance WP = distance YP |
| 4 | ∠WPZ and ∠ZPY are supplementary | if m∠WPY = 180, then ∠WPZ and ∠ZPY are supplementary |
| 5 | (m∠WPZ) + (m∠YPZ) = 180 | if ∠WPZ and ∠ZPY are supplementary, then (m∠WPZ) + (m∠YPZ) = 180 |
| 6 | m∠YPZ = 90 | if ∠YPZ is a right angle, then m∠YPZ = 90 |
| 7 | (m∠WPZ) + 90 = 180 | if (m∠WPZ) + (m∠YPZ) = 180 and m∠YPZ = 90, then (m∠WPZ) + 90 = 180 |
| 8 | m∠WPZ = 90 | if (m∠WPZ) + 90 = 180, then m∠WPZ = 90 |
| 9 | m∠WPZ = m∠YPZ | if m∠WPZ = 90 and m∠YPZ = 90, then m∠WPZ = m∠YPZ |
| 10 | distance PZ = distance PZ | distance PZ = distance PZ |
| 11 | △WPZ ≅ △YPZ | if distance WP = distance YP and m∠WPZ = m∠YPZ and distance PZ = distance PZ, then △WPZ ≅ △YPZ |
| 12 | distance WZ = distance YZ | if △WPZ ≅ △YPZ, then distance WZ = distance YZ |
| 13 | distance YZ = distance ZW | if distance WZ = distance YZ, then distance YZ = distance ZW |
| 14 | WXYZ is a rhombus | if WXYZ is a parallelogram and distance YZ = distance ZW, then WXYZ is a rhombus |
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