Proof: Tangent 2
Let's prove the following theorem:
if ∠ABC is a right angle, then tangent of (m∠BAC) = (distance CB) / (distance BA)
Proof:
Given
| 1 | ∠ABC is a right angle |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | ∠CBA is a right angle | if ∠ABC is a right angle, then ∠CBA is a right angle |
| 2 | tangent of (m∠BAC) = (distance CB) / (distance BA) | if ∠CBA is a right angle, then tangent of (m∠BAC) = (distance CB) / (distance BA) |
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