Proof: Pc 15

Let's prove the following theorem:

if the following are true:

instruction #1 is store src=7 addr=6 imm=0
the PC at time 15 = 1

then the PC at time 16 = 2

Proof:

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Given

1	instruction #1 is `store src=7 addr=6 imm=0`
2	the PC at time 15 = 1

Proof Table

#	Claim	Reason
1	the PC at time (15 + 1) = 1 + 1	if instruction #1 is `store src=7 addr=6 imm=0` and the PC at time 15 = 1, then the PC at time (15 + 1) = 1 + 1 (STORE Instruction Property 3)
2	15 + 1 = 16	15 + 1 = 16 (Fixed Value Statement)
3	1 + 1 = 2	1 + 1 = 2 (Fixed Value Statement)
4	the PC at time (15 + 1) = the PC at time 16	if 15 + 1 = 16, then the PC at time (15 + 1) = the PC at time 16 (Substitution)
5	the PC at time 16 = 2	if the PC at time (15 + 1) = 1 + 1 and the PC at time (15 + 1) = the PC at time 16 and 1 + 1 = 2, then the PC at time 16 = 2 (Transitive Property Application 2)

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