Proof: Byte 4 Stays the Same 0

Let's prove the following theorem:

if the following are true:

instruction #0 is load dst=7 addr=6 imm=0
the PC at time 0 = 0
value of cell 4 at time 0 = 11

then value of cell 4 at time 1 = 11

Proof:

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Given

1	instruction #0 is `load dst=7 addr=6 imm=0`
2	the PC at time 0 = 0
3	value of cell 4 at time 0 = 11

Proof Table

#	Claim	Reason
1	not (4 = 7)	not (4 = 7) (Fixed Value Statement)
2	value of cell 4 at time (0 + 1) = value of cell 4 at time 0	if instruction #0 is `load dst=7 addr=6 imm=0` and the PC at time 0 = 0 and not (4 = 7), then value of cell 4 at time (0 + 1) = value of cell 4 at time 0 (LOAD Instruction Property 2)
3	0 + 1 = 1	0 + 1 = 1 (Additive Identity Variation)
4	value of cell 4 at time (0 + 1) = value of cell 4 at time 1	if 0 + 1 = 1, then value of cell 4 at time (0 + 1) = value of cell 4 at time 1 (Substitution)
5	value of cell 4 at time 1 = value of cell 4 at time 0	if value of cell 4 at time (0 + 1) = value of cell 4 at time 1 and value of cell 4 at time (0 + 1) = value of cell 4 at time 0, then value of cell 4 at time 1 = value of cell 4 at time 0 (Transitive Property of Equality Variation 2)
6	value of cell 4 at time 1 = 11	if value of cell 4 at time 1 = value of cell 4 at time 0 and value of cell 4 at time 0 = 11, then value of cell 4 at time 1 = 11 (Transitive Property of Equality)

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