Proof: Byte 5 Stays the Same 13
Let's prove the following theorem:
if the following are true:
- instruction #5 is
beq left=3 right=4 imm=1 - the PC at time 13 = 5
- value of cell 5 at time 13 = 21
then value of cell 5 at time 14 = 21
Proof:
Given
| 1 | instruction #5 is beq left=3 right=4 imm=1 |
|---|---|
| 2 | the PC at time 13 = 5 |
| 3 | value of cell 5 at time 13 = 21 |
| # | Claim | Reason |
|---|---|---|
| 1 | value of cell 5 at time (13 + 1) = value of cell 5 at time 13 | if instruction #5 is beq left=3 right=4 imm=1 and the PC at time 13 = 5, then value of cell 5 at time (13 + 1) = value of cell 5 at time 13 |
| 2 | 13 + 1 = 14 | 13 + 1 = 14 |
| 3 | value of cell 5 at time (13 + 1) = value of cell 5 at time 14 | if 13 + 1 = 14, then value of cell 5 at time (13 + 1) = value of cell 5 at time 14 |
| 4 | value of cell 5 at time 14 = value of cell 5 at time 13 | if value of cell 5 at time (13 + 1) = value of cell 5 at time 14 and value of cell 5 at time (13 + 1) = value of cell 5 at time 13, then value of cell 5 at time 14 = value of cell 5 at time 13 |
| 5 | value of cell 5 at time 14 = 21 | if value of cell 5 at time 14 = value of cell 5 at time 13 and value of cell 5 at time 13 = 21, then value of cell 5 at time 14 = 21 |
Comments
Please log in to add comments