Proof: Byte 3 Stays the Same 9
Let's prove the following theorem:
if the following are true:
- instruction #5 is
beq left=3 right=4 imm=1 - the PC at time 9 = 5
- value of cell 3 at time 9 = 3
then value of cell 3 at time 10 = 3
Proof:
Given
| 1 | instruction #5 is beq left=3 right=4 imm=1 |
|---|---|
| 2 | the PC at time 9 = 5 |
| 3 | value of cell 3 at time 9 = 3 |
| # | Claim | Reason |
|---|---|---|
| 1 | value of cell 3 at time (9 + 1) = value of cell 3 at time 9 | if instruction #5 is beq left=3 right=4 imm=1 and the PC at time 9 = 5, then value of cell 3 at time (9 + 1) = value of cell 3 at time 9 |
| 2 | 9 + 1 = 10 | 9 + 1 = 10 |
| 3 | value of cell 3 at time (9 + 1) = value of cell 3 at time 10 | if 9 + 1 = 10, then value of cell 3 at time (9 + 1) = value of cell 3 at time 10 |
| 4 | value of cell 3 at time 10 = value of cell 3 at time 9 | if value of cell 3 at time (9 + 1) = value of cell 3 at time 10 and value of cell 3 at time (9 + 1) = value of cell 3 at time 9, then value of cell 3 at time 10 = value of cell 3 at time 9 |
| 5 | value of cell 3 at time 10 = 3 | if value of cell 3 at time 10 = value of cell 3 at time 9 and value of cell 3 at time 9 = 3, then value of cell 3 at time 10 = 3 |
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