Proof: Byte 3 Stays the Same 8
Let's prove the following theorem:
if the following are true:
- instruction #4 is
addi dst=4 src=4 imm=1 - the PC at time 8 = 4
- value of cell 3 at time 8 = 3
then value of cell 3 at time 9 = 3
Proof:
Given
| 1 | instruction #4 is addi dst=4 src=4 imm=1 |
|---|---|
| 2 | the PC at time 8 = 4 |
| 3 | value of cell 3 at time 8 = 3 |
| # | Claim | Reason |
|---|---|---|
| 1 | not (3 = 4) | not (3 = 4) |
| 2 | value of cell 3 at time (8 + 1) = value of cell 3 at time 8 | if instruction #4 is addi dst=4 src=4 imm=1 and the PC at time 8 = 4 and not (3 = 4), then value of cell 3 at time (8 + 1) = value of cell 3 at time 8 |
| 3 | 8 + 1 = 9 | 8 + 1 = 9 |
| 4 | value of cell 3 at time (8 + 1) = value of cell 3 at time 9 | if 8 + 1 = 9, then value of cell 3 at time (8 + 1) = value of cell 3 at time 9 |
| 5 | value of cell 3 at time 9 = value of cell 3 at time 8 | if value of cell 3 at time (8 + 1) = value of cell 3 at time 9 and value of cell 3 at time (8 + 1) = value of cell 3 at time 8, then value of cell 3 at time 9 = value of cell 3 at time 8 |
| 6 | value of cell 3 at time 9 = 3 | if value of cell 3 at time 9 = value of cell 3 at time 8 and value of cell 3 at time 8 = 3, then value of cell 3 at time 9 = 3 |
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