Proof: Byte 3 Stays the Same 5
Let's prove the following theorem:
if the following are true:
- instruction #5 is
beq left=3 right=4 imm=1 - the PC at time 5 = 5
- value of cell 3 at time 5 = 3
then value of cell 3 at time 6 = 3
Proof:
Given
| 1 | instruction #5 is beq left=3 right=4 imm=1 |
|---|---|
| 2 | the PC at time 5 = 5 |
| 3 | value of cell 3 at time 5 = 3 |
| # | Claim | Reason |
|---|---|---|
| 1 | value of cell 3 at time (5 + 1) = value of cell 3 at time 5 | if instruction #5 is beq left=3 right=4 imm=1 and the PC at time 5 = 5, then value of cell 3 at time (5 + 1) = value of cell 3 at time 5 |
| 2 | 5 + 1 = 6 | 5 + 1 = 6 |
| 3 | value of cell 3 at time (5 + 1) = value of cell 3 at time 6 | if 5 + 1 = 6, then value of cell 3 at time (5 + 1) = value of cell 3 at time 6 |
| 4 | value of cell 3 at time 6 = value of cell 3 at time 5 | if value of cell 3 at time (5 + 1) = value of cell 3 at time 6 and value of cell 3 at time (5 + 1) = value of cell 3 at time 5, then value of cell 3 at time 6 = value of cell 3 at time 5 |
| 5 | value of cell 3 at time 6 = 3 | if value of cell 3 at time 6 = value of cell 3 at time 5 and value of cell 3 at time 5 = 3, then value of cell 3 at time 6 = 3 |
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