Proof: Byte 3 Stays the Same 11
Let's prove the following theorem:
if the following are true:
- instruction #3 is
addi dst=5 src=5 imm=7 - the PC at time 11 = 3
- value of cell 3 at time 11 = 3
then value of cell 3 at time 12 = 3
Proof:
Given
| 1 | instruction #3 is addi dst=5 src=5 imm=7 |
|---|---|
| 2 | the PC at time 11 = 3 |
| 3 | value of cell 3 at time 11 = 3 |
| # | Claim | Reason |
|---|---|---|
| 1 | not (3 = 5) | not (3 = 5) |
| 2 | value of cell 3 at time (11 + 1) = value of cell 3 at time 11 | if instruction #3 is addi dst=5 src=5 imm=7 and the PC at time 11 = 3 and not (3 = 5), then value of cell 3 at time (11 + 1) = value of cell 3 at time 11 |
| 3 | 11 + 1 = 12 | 11 + 1 = 12 |
| 4 | value of cell 3 at time (11 + 1) = value of cell 3 at time 12 | if 11 + 1 = 12, then value of cell 3 at time (11 + 1) = value of cell 3 at time 12 |
| 5 | value of cell 3 at time 12 = value of cell 3 at time 11 | if value of cell 3 at time (11 + 1) = value of cell 3 at time 12 and value of cell 3 at time (11 + 1) = value of cell 3 at time 11, then value of cell 3 at time 12 = value of cell 3 at time 11 |
| 6 | value of cell 3 at time 12 = 3 | if value of cell 3 at time 12 = value of cell 3 at time 11 and value of cell 3 at time 11 = 3, then value of cell 3 at time 12 = 3 |
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