Proof: Byte 5 Stays the Same 18

Let's prove the following theorem:

if the following are true:

instruction #6 is addi dst=2 src=3 imm=0
the PC at time 18 = 6
value of cell 5 at time 18 = 4

then value of cell 5 at time 19 = 4

Instructions

Memory Cells

Program Counter	Time
0	0

LW Computer Simulator

Proof:

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Given

1	instruction #6 is `addi dst=2 src=3 imm=0`
2	the PC at time 18 = 6
3	value of cell 5 at time 18 = 4

Proof Table

#	Claim	Reason
1	not (5 = 2)	not (5 = 2) (Fixed Value Statement)
2	value of cell 5 at time (18 + 1) = value of cell 5 at time 18	if instruction #6 is `addi dst=2 src=3 imm=0` and the PC at time 18 = 6 and not (5 = 2), then value of cell 5 at time (18 + 1) = value of cell 5 at time 18 (ADDI Instruction Property 2)
3	18 + 1 = 19	18 + 1 = 19 (Fixed Value Statement)
4	value of cell 5 at time (18 + 1) = value of cell 5 at time 19	if 18 + 1 = 19, then value of cell 5 at time (18 + 1) = value of cell 5 at time 19 (Substitution)
5	value of cell 5 at time 19 = value of cell 5 at time 18	if value of cell 5 at time (18 + 1) = value of cell 5 at time 19 and value of cell 5 at time (18 + 1) = value of cell 5 at time 18, then value of cell 5 at time 19 = value of cell 5 at time 18 (Transitive Property of Equality Variation 2)
6	value of cell 5 at time 19 = 4	if value of cell 5 at time 19 = value of cell 5 at time 18 and value of cell 5 at time 18 = 4, then value of cell 5 at time 19 = 4 (Transitive Property of Equality)

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