Proof: Byte 1 Stays the Same 24
Let's prove the following theorem:
if the following are true:
- instruction #6 is
addi dst=2 src=3 imm=0 - the PC at time 24 = 6
- value of cell 1 at time 24 = 3
then value of cell 1 at time 25 = 3
Instructions
| Memory Cells |
|---|
| Program Counter | Time |
|---|---|
| 0 | 0 |
LW Computer Simulator
Proof:
Given
| 1 | instruction #6 is addi dst=2 src=3 imm=0 |
|---|---|
| 2 | the PC at time 24 = 6 |
| 3 | value of cell 1 at time 24 = 3 |
| # | Claim | Reason |
|---|---|---|
| 1 | not (1 = 2) | not (1 = 2) |
| 2 | value of cell 1 at time (24 + 1) = value of cell 1 at time 24 | if instruction #6 is addi dst=2 src=3 imm=0 and the PC at time 24 = 6 and not (1 = 2), then value of cell 1 at time (24 + 1) = value of cell 1 at time 24 |
| 3 | 24 + 1 = 25 | 24 + 1 = 25 |
| 4 | value of cell 1 at time (24 + 1) = value of cell 1 at time 25 | if 24 + 1 = 25, then value of cell 1 at time (24 + 1) = value of cell 1 at time 25 |
| 5 | value of cell 1 at time 25 = value of cell 1 at time 24 | if value of cell 1 at time (24 + 1) = value of cell 1 at time 25 and value of cell 1 at time (24 + 1) = value of cell 1 at time 24, then value of cell 1 at time 25 = value of cell 1 at time 24 |
| 6 | value of cell 1 at time 25 = 3 | if value of cell 1 at time 25 = value of cell 1 at time 24 and value of cell 1 at time 24 = 3, then value of cell 1 at time 25 = 3 |
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