Proof: Byte 1 Stays the Same 19
Let's prove the following theorem:
if the following are true:
- instruction #7 is
addi dst=4 src=4 imm=1 - the PC at time 19 = 7
- value of cell 1 at time 19 = 2
then value of cell 1 at time 20 = 2
Instructions
| Memory Cells |
|---|
| Program Counter | Time |
|---|---|
| 0 | 0 |
LW Computer Simulator
Proof:
Given
| 1 | instruction #7 is addi dst=4 src=4 imm=1 |
|---|---|
| 2 | the PC at time 19 = 7 |
| 3 | value of cell 1 at time 19 = 2 |
| # | Claim | Reason |
|---|---|---|
| 1 | not (1 = 4) | not (1 = 4) |
| 2 | value of cell 1 at time (19 + 1) = value of cell 1 at time 19 | if instruction #7 is addi dst=4 src=4 imm=1 and the PC at time 19 = 7 and not (1 = 4), then value of cell 1 at time (19 + 1) = value of cell 1 at time 19 |
| 3 | 19 + 1 = 20 | 19 + 1 = 20 |
| 4 | value of cell 1 at time (19 + 1) = value of cell 1 at time 20 | if 19 + 1 = 20, then value of cell 1 at time (19 + 1) = value of cell 1 at time 20 |
| 5 | value of cell 1 at time 20 = value of cell 1 at time 19 | if value of cell 1 at time (19 + 1) = value of cell 1 at time 20 and value of cell 1 at time (19 + 1) = value of cell 1 at time 19, then value of cell 1 at time 20 = value of cell 1 at time 19 |
| 6 | value of cell 1 at time 20 = 2 | if value of cell 1 at time 20 = value of cell 1 at time 19 and value of cell 1 at time 19 = 2, then value of cell 1 at time 20 = 2 |
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