Proof: Byte 1 Stays the Same 1
Let's prove the following theorem:
if the following are true:
- instruction #1 is
addi dst=2 src=0 imm=1 - the PC at time 1 = 1
- value of cell 1 at time 1 = 0
then value of cell 1 at time 2 = 0
Instructions
| Memory Cells |
|---|
| Program Counter | Time |
|---|---|
| 0 | 0 |
LW Computer Simulator
Proof:
Given
| 1 | instruction #1 is addi dst=2 src=0 imm=1 |
|---|---|
| 2 | the PC at time 1 = 1 |
| 3 | value of cell 1 at time 1 = 0 |
| # | Claim | Reason |
|---|---|---|
| 1 | not (1 = 2) | not (1 = 2) |
| 2 | value of cell 1 at time (1 + 1) = value of cell 1 at time 1 | if instruction #1 is addi dst=2 src=0 imm=1 and the PC at time 1 = 1 and not (1 = 2), then value of cell 1 at time (1 + 1) = value of cell 1 at time 1 |
| 3 | 1 + 1 = 2 | 1 + 1 = 2 |
| 4 | value of cell 1 at time (1 + 1) = value of cell 1 at time 2 | if 1 + 1 = 2, then value of cell 1 at time (1 + 1) = value of cell 1 at time 2 |
| 5 | value of cell 1 at time 2 = value of cell 1 at time 1 | if value of cell 1 at time (1 + 1) = value of cell 1 at time 2 and value of cell 1 at time (1 + 1) = value of cell 1 at time 1, then value of cell 1 at time 2 = value of cell 1 at time 1 |
| 6 | value of cell 1 at time 2 = 0 | if value of cell 1 at time 2 = value of cell 1 at time 1 and value of cell 1 at time 1 = 0, then value of cell 1 at time 2 = 0 |
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