The following example shows that when a LOAD instruction with dst = 5, addr = 1, and imm = 0 is executed, the computer looks up memory cell #1 and finds 3, then copies the value memory cell #3 (9) to memory cell #5. imm is 0 so the source address is unchanged.

Quiz (1 point)

• a + 0 = a
• 0 + a = a

• if the following are true:

  • instruction #i is load dst=dst addr=addr imm=imm
  • the PC at time t = i

  then value of cell dst at time (t + 1) = value of cell ((value of cell addr at time t) + imm) at time t

• if value of cell 1 at time 0 = 3, then (value of cell 1 at time 0) + 0 = 3 + 0

• if the following are true:

  • a = b
  • b = c

  then a = c

• if (value of cell 1 at time 0) + 0 = 3, then value of cell ((value of cell 1 at time 0) + 0) at time 0 = value of cell 3 at time 0

• if the following are true:

  • a = b
  • b = c

  then a = c

• if the following are true:

  • a = b
  • b = c

  then a = c

• if 0 + 1 = 1, then value of cell 5 at time (0 + 1) = value of cell 5 at time 1

• if the following are true:

  • a = b
  • a = c

  then b = c

Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.

Step	Claim	Reason (optional)	Error Message (if any)
1
2
3
4
5
6
7
8
9
10

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