Proof: JUMP Instruction Example 2
Let's prove the following theorem:
if the following are true:
- instruction #0 is
jump imm=jump_to - the PC at time 0 = 0
then value of cell x at time 1 = value of cell x at time 0
This example shows that a JUMP instruction does not change memory cell values. With some algebra, we prove that any memory cell at time 1 is equal to the cell at time 0.
Instructions
| Memory Cells |
|---|
| Program Counter | Time |
|---|---|
| 0 | 0 |
LW Computer Simulator
Proof:
Given
| 1 | instruction #0 is jump imm=jump_to |
|---|---|
| 2 | the PC at time 0 = 0 |
| # | Claim | Reason |
|---|---|---|
| 1 | value of cell x at time (0 + 1) = value of cell x at time 0 | if instruction #0 is jump imm=jump_to and the PC at time 0 = 0, then value of cell x at time (0 + 1) = value of cell x at time 0 |
| 2 | 0 + 1 = 1 | 0 + 1 = 1 |
| 3 | value of cell x at time (0 + 1) = value of cell x at time 1 | if 0 + 1 = 1, then value of cell x at time (0 + 1) = value of cell x at time 1 |
| 4 | value of cell x at time 1 = value of cell x at time 0 | if value of cell x at time (0 + 1) = value of cell x at time 1 and value of cell x at time (0 + 1) = value of cell x at time 0, then value of cell x at time 1 = value of cell x at time 0 |
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