Proof: BEQ Instruction Example 2
Let's prove the following theorem:
if the following are true:
- instruction #0 is
beq left=1 right=2 imm=2 - the PC at time 0 = 0
- value of cell 1 at time 0 = 1
- value of cell 2 at time 0 = 2
then the PC at time 1 = 1
The following example shows that when the value stored in the left cell (cell #1) is not equal to the value in the right cell (cell #2), the PC is incremented by 1.
Instructions
| Memory Cells |
|---|
| Program Counter | Time |
|---|---|
| 0 | 0 |
LW Computer Simulator
Proof:
Given
| 1 | instruction #0 is beq left=1 right=2 imm=2 |
|---|---|
| 2 | the PC at time 0 = 0 |
| 3 | value of cell 1 at time 0 = 1 |
| 4 | value of cell 2 at time 0 = 2 |
| # | Claim | Reason |
|---|---|---|
| 1 | not (1 = 2) | not (1 = 2) |
| 2 | value of cell 1 at time 0 = 2 = 1 = 2 | if value of cell 1 at time 0 = 1, then value of cell 1 at time 0 = 2 = 1 = 2 |
| 3 | value of cell 1 at time 0 = value of cell 2 at time 0 = value of cell 1 at time 0 = 2 | if value of cell 2 at time 0 = 2, then value of cell 1 at time 0 = value of cell 2 at time 0 = value of cell 1 at time 0 = 2 |
| 4 | value of cell 1 at time 0 = value of cell 2 at time 0 = 1 = 2 | if value of cell 1 at time 0 = value of cell 2 at time 0 = value of cell 1 at time 0 = 2 and value of cell 1 at time 0 = 2 = 1 = 2, then value of cell 1 at time 0 = value of cell 2 at time 0 = 1 = 2 |
| 5 | not (value of cell 1 at time 0 = value of cell 2 at time 0) = not (1 = 2) | if value of cell 1 at time 0 = value of cell 2 at time 0 = 1 = 2, then not (value of cell 1 at time 0 = value of cell 2 at time 0) = not (1 = 2) |
| 6 | not (value of cell 1 at time 0 = value of cell 2 at time 0) | if not (1 = 2) and not (value of cell 1 at time 0 = value of cell 2 at time 0) = not (1 = 2), then not (value of cell 1 at time 0 = value of cell 2 at time 0) |
| 7 | the PC at time (0 + 1) = 0 + 1 | if instruction #0 is beq left=1 right=2 imm=2 and the PC at time 0 = 0 and not (value of cell 1 at time 0 = value of cell 2 at time 0), then the PC at time (0 + 1) = 0 + 1 |
| 8 | 0 + 1 = 1 | 0 + 1 = 1 |
| 9 | the PC at time (0 + 1) = the PC at time 1 | if 0 + 1 = 1, then the PC at time (0 + 1) = the PC at time 1 |
| 10 | the PC at time 1 = 0 + 1 | if the PC at time (0 + 1) = the PC at time 1 and the PC at time (0 + 1) = 0 + 1, then the PC at time 1 = 0 + 1 |
| 11 | the PC at time 1 = 1 | if the PC at time 1 = 0 + 1 and 0 + 1 = 1, then the PC at time 1 = 1 |
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