Proof: Pc 4

Let's prove the following theorem:

if the following are true:

instruction #10 is store src=3 addr=1 imm=0
the PC at time 4 = 10

then the PC at time 5 = 11

Proof:

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Given

1	instruction #10 is `store src=3 addr=1 imm=0`
2	the PC at time 4 = 10

Proof Table

#	Claim	Reason
1	the PC at time (4 + 1) = 10 + 1	if instruction #10 is `store src=3 addr=1 imm=0` and the PC at time 4 = 10, then the PC at time (4 + 1) = 10 + 1 (STORE Instruction Property 3)
2	4 + 1 = 5	4 + 1 = 5 (Fixed Value Statement)
3	10 + 1 = 11	10 + 1 = 11 (Fixed Value Statement)
4	the PC at time (4 + 1) = the PC at time 5	if 4 + 1 = 5, then the PC at time (4 + 1) = the PC at time 5 (Substitution)
5	the PC at time 5 = 11	if the PC at time (4 + 1) = 10 + 1 and the PC at time (4 + 1) = the PC at time 5 and 10 + 1 = 11, then the PC at time 5 = 11 (Transitive Property Application 2)

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