Quiz (1 point)
Given that:
    
    
instruction #21 is 
    
    load dst=3 addr=1 imm=0the PC at time 21 = 21
    
    value of cell 1 at time 21 = 123
    
    value of cell 123 at time 21 = 5
    
    Prove that:
value of cell 3 at time 22 = 5
The following properties may be helpful:
    - a + 0 = a
- 21 + 1 = 22
- if the following are true: - instruction #i is load dst=dst addr=addr imm=imm
- the PC at time t = i
 - then value of cell dst at time (t + 1) = value of cell ((value of cell addr at time t) + imm) at time t 
- instruction #i is 
- if a = b, then a + c = b + c 
- if the following are true: - a = b
- b = c
 - then a = c 
- if (value of cell 1 at time 21) + 0 = 123, then value of cell ((value of cell 1 at time 21) + 0) at time 21 = value of cell 123 at time 21 
- if the following are true: - a = b
- b = c
 - then a = c 
- if the following are true: - a = b
- b = c
 - then a = c 
- if 21 + 1 = 22, then value of cell 3 at time (21 + 1) = value of cell 3 at time 22 
- if the following are true: - a = b
- a = c
 - then b = c 
Please write your proof in the table below. Each row should contain one claim. The last claim is the statement that you are trying to prove.