Proof: Byte 1 Stays the Same 5
Let's prove the following theorem:
if the following are true:
- instruction #11 is
addi dst=3 src=0 imm=3 - the PC at time 5 = 11
- value of cell 1 at time 5 = 127
then value of cell 1 at time 6 = 127
Proof:
Given
| 1 | instruction #11 is addi dst=3 src=0 imm=3 |
|---|---|
| 2 | the PC at time 5 = 11 |
| 3 | value of cell 1 at time 5 = 127 |
| # | Claim | Reason |
|---|---|---|
| 1 | not (1 = 3) | not (1 = 3) |
| 2 | value of cell 1 at time (5 + 1) = value of cell 1 at time 5 | if instruction #11 is addi dst=3 src=0 imm=3 and the PC at time 5 = 11 and not (1 = 3), then value of cell 1 at time (5 + 1) = value of cell 1 at time 5 |
| 3 | 5 + 1 = 6 | 5 + 1 = 6 |
| 4 | value of cell 1 at time (5 + 1) = value of cell 1 at time 6 | if 5 + 1 = 6, then value of cell 1 at time (5 + 1) = value of cell 1 at time 6 |
| 5 | value of cell 1 at time 6 = value of cell 1 at time 5 | if value of cell 1 at time (5 + 1) = value of cell 1 at time 6 and value of cell 1 at time (5 + 1) = value of cell 1 at time 5, then value of cell 1 at time 6 = value of cell 1 at time 5 |
| 6 | value of cell 1 at time 6 = 127 | if value of cell 1 at time 6 = value of cell 1 at time 5 and value of cell 1 at time 5 = 127, then value of cell 1 at time 6 = 127 |
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