Proof: Add Negative B
Let's prove the following theorem:
if a = b, then a + (b ⋅ (-1)) = 0
Proof:
Given
| 1 | a = b |
|---|
| # | Claim | Reason |
|---|---|---|
| 1 | a + (b ⋅ (-1)) = b + (b ⋅ (-1)) | if a = b, then a + (b ⋅ (-1)) = b + (b ⋅ (-1)) |
| 2 | b + (b ⋅ (-1)) = 0 | b + (b ⋅ (-1)) = 0 |
| 3 | a + (b ⋅ (-1)) = 0 | if a + (b ⋅ (-1)) = b + (b ⋅ (-1)) and b + (b ⋅ (-1)) = 0, then a + (b ⋅ (-1)) = 0 |
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